What is the hardest multiplication problem in the world?

The hardest multiplication was six times eight, which students got wrong 63% of the time (about two times out of three). This was closely followed by 8×6, then 11×12, 12×8 and 8×12. Pupils found 8×7 nearly as tricky as former education minister Stephen Byers, who once famously answered that particular sum incorrectly.

Is brilliant free for students?

Brilliant.org is a free online mathematics and science problem solving website for bright young students around the world.

What percentage of entering freshmen require remedial classes?

In the United States, research shows that anywhere from 40 percent to 60 percent of first-year college students require remediation in English, math, or both. Remedial classes increase students’ time to degree attainment and decrease their likelihood of completion.

What degrees require no math?

Medical and healthcare careers

• Nursing: Most licensed practical or vocational nursing programs only require one or two basic math courses.
• Dental Hygiene: As a dental hygienist, you won’t be using that much math.
• Acupuncturist: You won’t need any more math credits to become an acupuncturist.

What is the longest math equation?

What is the longest equation in the world? According to Sciencealert, the longest math equation contains around 200 terabytes of text. Called the Boolean Pythagorean Triples problem, it was first proposed by California-based mathematician Ronald Graham, back in the 1980s.

Does remedial math affect GPA?

The course work is preparatory and not college-level. Similarly, the grades in a remedial course don’t usually affect the student’s grade-point average, other than for financial aid assessment. College classes do contribute toward the student’s degree, and the grades you receive in those classes do count on your GPA.

What is the most difficult math equation?

In 2019, mathematicians finally solved a math puzzle that had stumped them for decades. It’s called a Diophantine Equation, and it’s sometimes known as the “summing of three cubes”: Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.